ÄÚÈÝ·¢²¼¸üÐÂʱ¼ä : 2026/4/10 2:02:12ÐÇÆÚÒ» ÏÂÃæÊÇÎÄÕµÄÈ«²¿ÄÚÈÝÇëÈÏÕæÔĶÁ¡£
µÚÒ»Õ »¯Ñ§ÈÈÁ¦Ñ§»ù´¡
Ò»¡¢ÅжÏÌâ
1£® ·ÅÈÈ·´Ó¦ÊÇ×Ô·¢µÄ¡££¨ £©
2£® ·´Ó¦µÄ¦¤rHm¾ÍÊÇ·´Ó¦µÄÈÈЧӦ¡££¨ £©
3£® ÔÚ¸ø¶¨Ìõ¼þÏ£¬ÏÂÁз´Ó¦·½³ÌʽËù±í´ïµÄ·´Ó¦²úÉúµÄÈÈÁ¿ÊÇÒ»ÏàͬµÄÖµ¡££¨ £©
2H2(g) + O2(g) = 2H2O(l) ÓëH2(g) +
1 O2(g) = H2O(l) 24£® ·´Ó¦µÄ¦¤rSmΪÕýÖµ£¬¸Ã·´Ó¦ÊÇ×Ô·¢µÄ¡££¨ £©
5£® Èç¹û·´Ó¦µÄ¦¤rHmºÍ¦¤rSm½ÔΪÕýÖµ£¬ÉýÎÂʱ¦¤rGm¼õÉÙ¡££¨ £© 6£® ·²ÊǼª²¼Ë¹×ÔÓÉÄܽµµÍµÄ¹ý³ÌÒ»¶¨ÊÇ×Ô·¢¹ý³Ì¡££¨ £© 7£® ·Ö×ÓÊýÔö¼ÓµÄ·´Ó¦¦¤rSmÒ»¶¨ÎªÕýÖµ¡££¨ £©
8£® »¯Ñ§·´Ó¦µÄ¶¨Ñ¹ÈÈÓë;¾¶Î޹أ¬¹ÊÆäΪ״̬º¯Êý¡££¨ £© 9£® »¯Ñ§·´Ó¦µÄ¶¨Ñ¹ÈȲ»ÊÇ״̬º¯Êý£¬µ«Óë;¾¶Î޹ء££¨ £©
10£®Ö¸¶¨Î¶ÈÏ£¬ÔªËØÎȶ¨µ¥ÖʵĦ¤fH?m =0 ¡¢¦¤fG?m=0¡¢ S?m=0 ¡££¨ £©
11£®Ó¦ÓøÇ˹¶¨ÂÉ£¬²»½ö¿ÉÒÔ¼ÆË㻯ѧ·´Ó¦µÄ¦¤rHm, »¹¿É¼ÆË㦤rUm¡¢ ¦¤rGm ¡¢¦¤rSmµÈ¡££¨ £© 12£®¶ÔÓÚ¦¤rS?m>0µÄ·´Ó¦£¬±ê׼״̬Ï£¬¸ßÎÂʱ¾ù¿ÉÄÜÕýÏò·´Ó¦¡££¨ £© 13£®¦¤rG?m<0µÄ·´Ó¦Ò»¶¨ÄÜ×Ô·¢½øÐС££¨ £©
14£®ÄÜȼÉÕµÄÎïÖʺ¬ÓÐÈÈÁ¿£¬·´Ö®Ôò²»º¬ÓÐÈÈÁ¿¡££¨ £©
1
¶þ¡¢Ñ¡ÔñÌâ
1¡¢ÏÂÁи÷×é¾ùΪ״̬º¯ÊýµÄÊÇ£¨ £©
A£®U¡¢H¡¢S¡¢P¡¢V¡¢T B£® U¡¢H¡¢S¡¢W¡¢Q¡¢G C£®¦¤U¡¢¦¤H¡¢¦¤S¡¢W¡¢Q¡¢¦¤G D£®QP¡¢QV¡¢W¡¢P¡¢V¡¢T
2. ÏÂÁÐÎïÖÊÖУ¬¦¤fG?m = 0 µÄÊÇ£¨ £©
A. Br2( g) B. Br2(l) C. Br2(aq) D. Br ¨C(aq)
3¡¢ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ£º£¨ £©
A. ʯīµÄìʲ»ÎªÁã B. µÈÎÂÌõ¼þÏÂ, ¦¤rGm? = ¦¤rH?m ¨C T¦¤rSm? C. ·´Ó¦µÄìʱäÔ½´ó,·´Ó¦ËÙÂÊÔ½´ó.
D. ÎÞÂÛÈκÎÇé¿öÏÂ,Ö»Òª¦¤S>0,¸Ã·´Ó¦Ò»¶¨ÊÇ×Ô·¢·´Ó¦. 4¡¢¾ßÓÐ×îСĦ¶ûìØµÄÎïÖÊÊÇ£¨ £©
A. Br2(l) B. NaCl(s) C. Na(s) D. Cl2(g)
5£® Èôij·´Ó¦µÄ¦¤rGm? = 10KJ.mol-1£¬ÓÉ´Ë¿ÉÍÆ¶Ï¸Ã·´Ó¦£¨ £©
A¡¢¦¤rHm?>0 ¦¤rSm?<0 B. Ò»¶¨²»ÄÜ×Ô·¢½øÐÐ C. ÔÚ±ê׼״̬ÏÂÒ»¶¨²»ÄÜ×Ô·¢½øÐÐ D. ÔڷDZê׼״̬ÏÂÒ»¶¨²»ÄÜ×Ô·¢½øÐÐ
6£® ÔÚ373K£¬101325Paʱ£¬Ë®Õô·¢ÎªË®ÕôÆûµÄ¹ý³ÌÖУ¬ÌåϵµÄÈÈÁ¦Ñ§º¬ÊýµÄ±äÁ¿ÎªÁãµÄ£¨ £©
A£®¦¤rH?m B. ¦¤rG?m C. ¦¤rSm? D. ¦¤rUm
7£® ÒÑÖªHClµÄ¦¤fH?m = 431KJ.mol-1£¬Ôò¿ÉÅжÏÏÂÁз´Ó¦£º
H2(g) + Cl2(g) = 2HCl(g) µÄ¦¤rH?mΪ£º£¨ £©
A. ¨C431KJ.mol-1 B. 862KJ.mol-1 C. ¨C862KJ.mol-1 D. ÎÞ·¨ÅжÏ
3
8£® ±íʾ CO2µÄ±ê׼Ħ¶ûÉú³Éìʵķ´Ó¦ÊÇ£¨ £©
A. CO(g) + 1/2O2(g) = CO2(g) ¦¤rH?m = £283.0KJ.mol-1 B. C(½ð¸Õʯ ) + O2(g) = CO2(g) ¦¤rH?m = £395.38KJ.mol-1 C. 2C(ʯī) + 2O2(g) = 2CO2(g) ¦¤rH?m = £787.0KJ.mol-1 D. C(ʯī) + O2(g) = CO2(g) ¦¤rH?m = £393.5KJ.mol-1 9£® °´¹æ¶¨£¬ÏÂÁÐÎïÖʵıê׼Ħ¶ûÉú³ÉìÊΪÁãµÄÊÇ£¨ £©
A. C(½ð¸Õʯ) B. O3(g) C. Br2(l) D. I2(g) 10£®ÏÂÁз´Ó¦ÖÐÄĸöÊDZíʾ¦¤fH?m (AgI,s)µÄ·´Ó¦Ê½£¨ £©
A. Ag+(aq) + I-(aq) = AgI(s) B. 2 Ag(s) + I2(s) = 2AgI(s) C. 2 Ag(s) + I2(g) = 2AgI(s) D. Ag(s) + 1/2I2(s) = AgI(s)
11£® ÒÑÖª C£¨Ê¯Ä«£©+ O2(g) = CO2(g) ¦¤fH?m = £393.5KJ.mol-1 fH?
m =
£395.8KJ.mol-1
Ôò£º C£¨Ê¯Ä«£©?C(½ð¸Õʯ)µÄ¦¤rH?mµÈÓÚ£¨ £©
A. ¨C789.3KJ.mol-1 B. 2.3KJ.mol-1 C. ¨C2.3KJ.mol-1 D. 789.3KJ.mol-1
12£® Ò»¶¨Î¶ÈÏ£¬ÏÂÁз´Ó¦ÖÐÄÇÒ»¸ö·´Ó¦µÄ¦¤rS?mÖµ×î´ó£¨ £©
A. CaSO4(s) + 2H2O(l) = CaSO4.2H2O(s) B.
MgCO3(s) = MgO(s) + CO2(g)
C. 2SO2(g) + O2(g) = 2SO3(g) D. H2(g) + Cl2(g) = 2HCl(g)
13£®·´Ó¦MgCl2(s) = Mg(s) + Cl2(g), ¦¤rHm¦¨
>0,±ê׼״̬Ï£¬´Ë·´Ó¦£º£¨ £© A. µÍÎÂ×Ô·¢ B. ¸ßÎÂ×Ô·¢
C. ÈκÎζȾù×Ô·¢ D. ÈκÎζȾù²»¿ÉÄÜ×Ô·¢
4
C£¨½ð¸Õʯ£©+ O2(g) = CO2(g) ¦¤