Äê²ú22Íò¶Ö¾Û±ûÏ©Éú²ú¹¤ÒÕÉè¼Æ ÏÂÔØ±¾ÎÄ

ÄÚÈÝ·¢²¼¸üÐÂʱ¼ä : 2025/6/16 5:22:24ÐÇÆÚÒ» ÏÂÃæÊÇÎÄÕµÄÈ«²¿ÄÚÈÝÇëÈÏÕæÔĶÁ¡£

ÉòÑô½¨Öþ´óѧ±ÏÒµÉè¼Æ

T1=298.15k, T2=338.15k

²é»¯¹¤ÊÖ²áµÃC3H6µÄa=8.256,b=2.174¡Á10-1, c=-9.692¡Ál0-5,d=1.548¡Á10-8 ½«T1=298.15k, T2=338.15k´úÈë:

2CO P=16.512+2.174¡Á 10-1¡Á(338.15+298.15)-9.692¡Á 10-5¡Á(338.152+298.152) +1.584¡Á10-8¡Á(338.153+298.153) =136.18 J/ (mo1¡¤k) CO P=68.091/ (mol¡¤k)

²é»¯¹¤ÊÖ²áµÃC3H6µÄa=1.410,b=19.057¡Á10-3, c=-24.501¡Á10-6. d=16.391¡Á10-9 ½«T1=298.15k, T2=338.15k´úÈë:

2CO P=2.82+19.057¡Á10-3¡Á(338.15+298.15)-24.051¡Á10-6¡Á(338.152+298.152) +16.391¡Á10-9¡Á(338.153+298.153) =11.126 J/ (mo1¡¤k) CO P=5.563 J/ (mol¡¤k) ¦¤H3=¡ÆnCO P (338.15-298.15)

=£¨(45000-27600)/(1.0¡Á105 )¡Á19000+1600/42¡Á68.09+100/28¡Á5.563) ¡Á(338.15-298.15) =(3306+2593.9+19.87)¡Á40 =2.368¡Á105kJ/h ¦¤H=¦¤H1+¦¤H2+¦¤H3

=-7.483¡Á105-2.372¡Á 107+2.368¡Á106 =-2.423¡Á107 kJ/h

2.2É豸¹¤ÒÕ¼ÆËãÓëÑ¡ÐÍ

2.2.1ÎÔʽ½Á°è´²·´Ó¦Æ÷

ÎÔʽ½Á°è´²·´Ó¦Æ÷:µÚÒ»¾ÛºÏ·´Ó¦Æ÷ºÍµÚ¶þ¾ÛºÏ·´Ó¦Æ÷µÄÎïÁϺâËãºÍÈÈÁ¿ºâËãÒѾ­Ëã³öÏÂÃæ¶ÔÆä½øÐÐÑ¡ÐÍ,ÓÉ×ÊÁϵõ½Amoco-CDÆøÏà¾ÛºÏµÄÍ£Áôʱ¼äÊÇ5·ÖÖÓ,¿ÉÒԵóö¾ÛºÏ·´Ó¦Æ÷µÄ³ß´ç´óС±ê×¼,·´Ó¦Æ÷µÄÌî³ä±ÈΪ70%µÃ³ö:

ÔÚ·´Ó¦Æ÷ÄÚµÄѹÁ¦ÊÇ2.2MPa,ζÈÊÇ70¡æÒÑÖªÔÚ±ê×¼Çé¿öÏÂÖ÷񻮿ÌåµÄÃܶȿÉÇó³öÔÚ·´Ó¦Çé¿öϵÄÃܶÈ.

ÔÚ·´Ó¦Ìõ¼þϵÄÖ÷Ë£ÆøÌåµÄÃܶÈÊÇ:41.48 kg/m3 V=(46000/41.48)¡Á5/60¡Â0.7=132.02m3/h

25

ÉòÑô½¨Öþ´óѧ±ÏÒµÉè¼Æ

¿ÉÒÔÍÆËã³öÆäR=2m,L=10.5m.

2.2.2¾»»¯ËþµÄ¹¤ÒÕ¼ÆËã¼°Ñ¡ÐÍ

Ô­ÁϾ»»¯ËþµÄÊýÄ¿½Ï¶àµ«ÊǾ»»¯µÄ½øÁϺͳöÁϼ°¾»»¯³É¶¼Ïà²î²»¶à,ËùÒÔ½öÒÔ³ýSO2µÄ¾»»¯ËþΪÀý½øÐÐÏêϸµÄ¹¤ÒÕ¼ÆËã,ÆäËûµÄ¾»»¯ËþͬÀí. SO2µÄÌå»ý·ÖÊýΪ0.006%;ÒªÇóµÄÎüÊÕÂʦÕA=99% ¼ºÖªËþÄڵľø¶ÔѹÁ¦Îª1 MPa,Çó³öÈëËþµÄÆøÌåÌå»ýÁ÷Á¿:

0.1013 MPa¶ÔÓ¦µÄÆøÌåÃܶÈÊÇ1.914 kg/m3.ËùÒÔ¿ÉÒÔÇó³öÔÚ1 MPaϵıûÏ©ÃܶÈ: ???P2??11?1.914??18.89kg/m3 P20.1013 ¼ºÖªÆäƽ¾ùĦ¶ûÁ¿ÊÇ42kg/kmol.¼ÙÉèÏ´µÓË®µÄºÄÓÃÁ¿Îª300000kg/h¡£¶øÇÒÎüÊÕËþ²ÅÓõÄÊÇ25mm¡Á25mm¡Á1.2mmµÄËÜÁϱ«¶û»·ÒÔÂÒ¶Ñ·½Ê½³äÌî.ÌîÁϲãµÄÌå»ý´«ÖÊϵÊý KYa=146kmo1/(m3¡¤h);²Ù×÷Ìõ¼þÏÂµÄÆ½ºâ¹ØÏµÎªY=15X. ÇåË®µÄÃܶÈÊǦÑL=1000 kg/m3;

Ôò: wË®/w±û¡Á (¦Ñ±û/¦ÑË®)0.5

=300000/47000 ¡Á(8.89/1000)0.5 =0.88

²é»¯¹¤Ô­ÀíµÄÂÒ¶ÑÌîÁÏ·ºµãÏß¿ÉÒԵõ½ºá×ø±êΪ0.88ʱºòµÄ×Ý×ø±êµÄÖµÊÇ0.025¼´ uF2§¶F¦·/g¡Á(¦Ñ±û/¦ÑÆø)¦ÌL0.2 =0.025

²é»¯¹¤ÊýÖµµÃµ½25mm¡Á25mm¡Á1.2mmµÄËÜÁϱ«¶û»·(ÂÒ¶Ñ)µÄÌîÁÏÒò×Ó§æ= 285m-1;ÓÖÒòΪҺÏàΪÇåË®,¹ÊÒºÌåÃܶÈУÕýϵÊý¦×=1;Ë®µÄð¤¶È¦ÌL =lMPa.·ºµãÆøËÙΪ .?

Umax?0.025?9.81?1000285?1?18.89?1?0.213m/s

¼ÙÉè¿ÕËþµÄ±ûÏ©Á÷ËÙΪ·ºµãÆøËÙµÄ80%¼´: u=0.8¡ÁUmax=0.8¡Á0.213 =0.170m/s

ÔòD?4Vs/?u?4?47000/18.89?3600/(??0.17)?3.28m ¾­¹ýÔ²ÕûD=3.5m

¶ÔÓÚÎüÊÕ²Ù×÷,Óô«Öʵ¥Ôª·¨¼ÆËãÌîÁϲã¸ß¶È¡£

V=47000/42¡Á(1-0.00006)=1118.08 kmol/h L=300000/18=18667kmol/h ¦¸=¦Ð/4¡ÁD2=3.14/4¡Á3.52 =9.6m2

S=mV/L

=15¡Á1118.08/18667

26

ÉòÑô½¨Öþ´óѧ±ÏÒµÉè¼Æ

=0.904 ÇåË®ÎüÊÕ,X2=0,Y* 2=0.

Y1?Y2*1 ?*Y2?Y21??AÔòHOG=V/KYa¦¸ . =1118.08/(146¡Á9.6) =0.80

NOG=1/(1-S)In ((1-S)(Y1-Y* 2)/(Y2-Y* 2)+S) =1.38 Z=HOG¡¤NOG =11.04

ʵ¼ÊÌîÁϲã¸ß¶È: Z'=1.5Z=1.5¡Á11.04=16.56m

ÒÔΪÌîÁϲã´óÓÚ6Ã×ËùÒÔ·Ö³ÉÈý¶Îÿ¶Ï6Ã×,ÁíÍ⻹Ҫ¿¼ÂDZ¸ÓöÎËùÒÔÊÇ4¶Îÿ¶Î6Ã×ÓÉ´Ë¿ÉÒÔÍÆËã³öËþµÄÊý¾ÝΪ:

L=6¡Á4+ (5+1.5+1+1+1) =30m S??4D2?3.143.52=9.6 42.2.3Ñ­»·ÀäÈ´Æ÷µÄ¹¤ÒÕ¼ÆËã

Ñ­»·ÀäÈ´Æ÷µÄ¹¤ÒÕ¼ÆËã ÈÈÆøÌå½ø¿ÚζÈ:

±ûÏ©: 70¡æ ³ö¿ÚζÈ: 40¡æ ÇâÆø: 70¡æ ³ö¿ÚζÈ: 40¡æ ÆøÌåµÄÖÊÁ¿Á÷Á¿: ±ûÏ©: 1600kg/h ÇâÆø: 50kg/h Ñ­»·ÀäÒºÌå½ø¿ÚζÈ: 20¡æ ³ö¿ÚζÈ: 400¡æ ÈÈÁ÷Á¿: 0.4722kg/s

»»ÈÈÆ÷Óɧ¶25mm¡Á2.5mmµÄ¹Ü×é³É ÆøÌåµÄƽ¾ù±ÈÈÈ: 1.2kJ/kg¡¤¡æ

¹ÜÄ򵀮øÌåµÄƽ¾ùζÈt=(40+70)¡Â2=50¡æ,¸ÃζÈÏÂµÄÆøÌåÌØÐÔÊý¾Ý²éѯµÃ ¦Ñ=12.93kg/m3 ¦Ì=2.16kg/(m¡¤s) CP=2.005¡Á103J/(kg¡¤¡æ) ¦Ë=350 W/m ¡¤¡æ

27

?

ÉòÑô½¨Öþ´óѧ±ÏÒµÉè¼Æ

¹ÜÄÚ²àÆøÌåµÄ¦ÁiΪ150W/m2¡¤¡æ ¹ÜÍâ²àÒºÌåµÄ¦ÁoÈ¡4233W/m2¡¤¡æ ¸ÖµÄ¦ËΪ45W/m¡¤¡æ

ÓÉ¡¶ÎﻯÊֲᡷ²éµÃÆøÌåµÄÎÛ¹¸ÈÈ×èRsi=0.5¡Á10-3m2¡¤¡æ/W,ÇÒ½üËÆÈÏΪ Rsi =Rso ÓÉ

ddbd11?0?Rsi0?0?Rso?ko?1didi?dm??0.025/(150?0.02)?0.5?10?3?0.025/0.02?0.0025?0.025/(45?0.0225)?0.5?10?3?1/4233?0.1m2?OC/W

0

ko=10W/m2¡¤C

»»ÈÈÆ÷´«ÈÈÃæ»ý¿É¸ù¾Ý´«ÈÈËÙÂÊ·½³ÌÇóµÃ,¼´ S?»»ÈÈÆ÷µÄ´«ÈÈÁ¿Îª

Q, 2-7 ku?tmQ?WhCph(T1?T2)

?0.4722?1.2?103?(313.15?343.15)??1.69?10kw4

?tm?(?t2??t1)/ln(?t2/?t1)?((343.15?313.15)?(313.15?293.15))/ln(313.15/293.15) ?24.7oC S?Q/k0?tm?70m2 ËùÒÔÀäÈ´Æ÷µÄ´«ÈÈÃæ»ýΪ70m2.

2.2.4Ðý·ç·ÖÀëÆ÷µÄ¼ÆËã

ÔÚ¾Û±ûÏ©·ÖÀë¹ý³ÌÖеÄÐý·ç·ÖÀëÆ÷²ÉÓÃXLPB-7.0ÐÍ,É豸Ͳ¾¶¦Õ700,½ø¿ÚÆøËÙ18m/s×óÓÒ.

Óɹ«Ê½ÆøÌå´¦ÀíÁ¿

L=3600¡ÁF¡ÁV 2-8

F=0.175D2 2-9

28