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oracle 数据库增删改查练习50例-答案

一、建表--学生表drop table student;create table student (sno varchar2(10,sname varchar2(10,sage date,ssex varchar2(10;insert into student values('01','赵雷',to_date('1990/01/01','yyyy/mm/dd','男';insert into student values('02','钱电',to_date('1990/12/21','yyyy/mm/dd','男';insert into student values('03','孙风',to_date('1990/05/20','yyyy/mm/dd','男';insert into student values('04','李云',to_date('1990/08/06','yyyy/mm/dd','男';insert into student values('05','周梅',to_date('1991/12/01','yyyy/mm/dd','女';insert into student values('06','吴兰',to_date('1992/03/01','yyyy/mm/dd','女';insert into student values('07','郑竹',to_date('1989/07/01','yyyy/mm/dd','女';insert into student values('08','王菊

',to_date('1990/01/20','yyyy/mm/dd','女';--课程表drop table course;create table course (cno varchar2(10,cname varchar2(10,tno varchar2(10;insert into course values ('01','语文','02';insert into course values ('02','数学','01';insert into course values ('03','英语','03';

--教师表drop table teacher;create table teacher (tno varchar2(10,tname varchar2(10;insert into teacher values('01','张三';insert into teacher values('02','李四';insert into teacher values('03','王五';

--成绩表drop table sc;create table sc (sno varchar2(10,cno varchar2(10,score number(18,1;insert into sc values('01','01',80.0;insert into sc values('01','02',90.0;insert into sc values('01','03',99.0;insert into sc values('02','01',70.0;insert into sc values('02','02',60.0;insert into sc values('02','03',80.0;insert into sc values('03','01',80.0;insert into sc values('03','02',80.0;insert into sc values('03','03',80.0;insert into sc values('04','01',50.0;insert into sc values('04','02',30.0;insert into sc values('04','03',20.0;insert into sc values('05','01',76.0;insert into sc values('05','02',87.0;insert into sc values('06','01',31.0;insert into sc values('06','03',34.0;insert into sc values('07','02',89.0;insert into sc values('07','03',98.0;

commit;

二、查询1.1、查询同时存在\课程和\课程的情况select s.sno, s.sname, s.sage, s.ssex, sc1.score, sc2.score from student s, sc sc1, sc sc2 where s.sno = sc1.sno and s.sno = sc2.sno and sc1.cno = '01' and sc2.cno = '02';

1.2、查询必须存在\课程，\课程可以没有的情况

select t.*, s.score_01, s.score_02 from student t inner join (select a.sno, a.score score_01, b.score score_02 from sc a left join (select * from sc where cno = '02' b on (a.sno = b.sno where a.cno = '01' s on (t.sno = s.sno;

2.1、查询同时'01'课程比'02'课程分数低的数据

select s.sno, s.sname, s.sage, s.ssex, sc1.score, sc2.score from student s, sc sc1, sc sc2 where s.sno = sc1.sno and s.sno = sc2.sno and sc1.cno = '01' and sc2.cno = '02' and sc1.score < sc2.score;

2.2、查询同时'01'课程比'02'课程分数低或'01'缺考的数据select s.sno, s.sname, s.sage, s.ssex, t.score_01, t.score_02 from student s, (select b.sno, a.score score_01, b.score score_02 from (select * from sc where cno = '01' a, (select * from sc where cno = '02' b where a.sno(+ = b.sno t where s.sno = t.sno and (t.score_01 < t.score_02 or t.score_01 is null;

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩select s.sno, s.sname, t.avg_score avg_score from student s, (select sno, round(avg(score, 2 avg_score from sc group by sno having avg(score >= 60 order by sno t where s.sno = t.sno;

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩4.1、有考试成绩，且小于60分select s.sno, s.sname, t.avg_score avg_score from student s,

(select sno, round(avg(score, 2 avg_score from sc group by sno having avg(score < 60 order by sno t where s.sno = t.sno;

4.2、包括没有考试成绩的数据select g.* from (select s.sno, s.sname,

nvl(t.avg_score, 0 avg_score from student s, (select sno, round(avg(score, 2 avg_score from sc group by sno order by sno t where s.sno = t.sno(+ g where g.avg_score < 60;

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩5.1、查询所有成绩的（不含缺考的）。select s.sno,s.sname,c.count_cno,c.sum_scorefrom student s,(select sno,count(cno count_cno,sum(score sum_score from sc group by sno order by sno c

where s.sno = c.sno

5.2、查询所有成绩的(包括缺考的。select a.s_sno, a.s_sname, nvl(a.c_cno, 0, a.s_score from (select s.sno s_sno, s.sname s_sname, c.count_cno c_cno, c.sum_score s_score from student s, (select sno, count(cno count_cno, sum(score sum_score from sc group by sno order by sno c where s.sno = c.sno(+ a

6、查询\李\姓老师的数量 （有几个老师姓李）select count(tn from (select tno, substr(tname, 0, 1 tn from teacher where substr(tname, 0, 1 = '李' a;

7、哪些学生上过张三（老师）的课select st.* from student st, course co, teacher te, sc where te.tno = co.tno and co.cno = sc.cno and sc.sno = st.sno and te.tname = '张三'

8、哪些学生没上过张三（老师）的课select * from studentminus select st.* from student st, course co, teacher te, sc where te.tno = co.tno and co.cno = sc.cno and sc.sno = st.sno and te.tname = '张三'

9、查询 '01' '02'都学过的同学的信息select st.* from student st, (select * from sc where cno = '01' a, (select * from sc where cno = '02' b where st.sno = a.sno and st.sno = b.sno