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COA考试资料

前二章作业

1. 计算机的四个基本功能（Functions）是什么？(P6带圆点处)

2. 在计算机的top-level structure view中，四个structural components 是什么？P10 Figure 1.4 3. 谁提出了 store-program concept ?(P17)你能用汉语简单地描述这个存储程序的概念吗？ 4. CPU的英文全称是什么(P9)？汉语意义是什么？P11 CPU构造 Figure 1.5 5. ALU的英文全称是什么？汉语意义是什么？(P9)

6. Von Neumann 的IAS机的五大部件都是什么？(P20带圆点处)

7. 在第一章中我们认识到的四个结构性部件（第2题）与Von Neumann的IAS机（第6题）中部件

有本质差别吗？

8. Fundamental Computer Elements 有哪几个（P28 figure 2.6）？它们与计算机的四个基本功能的关

系是什么？

9. Moore’s Law在中文翻译为什么？它描述了什么事物的一般规律？(P24 double every 18 months) 10. 本书的次标题和第二章第二节标题均为“Designing for Performance”,Performance 主要指什么(P37

带圆点处)？Performance Balance的（balance）平衡要平衡什么（P38）？

11. 本书作者将他要研究的范围局限在“desktop, workstation , server“中，它们的中文名称是什么(桌面体、工作站和服务器)？各自的工作范围是什么？(P37)

Chapter 3 Homework

1.PC means _ （P53 相关的 IR 、MAR、 MBR 、I/O、 AR、 I/OBR means牢记） A. personal computer B. programming controller C. program counter D. portable computer

PC——存放下一条指令的地址（address of next instruction） MAR——存放本条指令的地址(address of the instruction)

MBR——存放取得的内容(comtents )

2. PC holds A

A. address of next instruction B. next instruction C. address of operand D. operand

3. At the end of fetch cycle, MAR holds ___(P54 fetch cycle 的步骤，对应12章的内容P422) A. address of instruction B. instruction C. address of operand D. operand

4. Interrupt process steps are __P61（相当重要） A. suspending , resuming , branching & processing B. branching , suspending , processing & resuming C. suspending , branching , processing & resuming D. processing , branching , resuming & suspending

5. A unsigned binary number is n bits, so it is can represent a value in the range between _________ .（未带符号）

A. 0 to n-1 B. 1 to n C. 0 to 2n-1 D. 1 to 2n

6.The length of the address code is 32 bits, so addressing range (or the range of address) is ________________. (1K=210B 1M=210K 1G=210M) A. 4G B.from –2G to 2G C.4G-1 D. from 1 to 4G

7.There are three kinds of BUSes. Which is not belong to them?(P70 Figure 3.16) A. address bus B. system bus C. data bus D. control bus

第四章

一：选择题

1. The computer memory system refers to __(P97 区分Internal Memory和External memory)_

A. RAM Internal Memory(内部存储器)——register,main memory,ache B. ROM External memory（外部存储器）——disk C. Main memory

D. Register , main memory, cache, external memory

2. If the word of memory is 16 bits, which the following answer is right ?

A. The address width is 16 bits

B. The address width is related with 16 bits

C. The address width is not related with 16 bits D. The address width is not less than 16 bits

3. The characteristics of internal memory compared to external memory(P100 figure 4.1 图中从上往下看：速度变

慢，容量增大，单位成本降低)

A. Big capacity, high speed, low cost B. Big capacity, low speed, high cost C. small capacity, high speed, high cost D. small capacity, high speed, low cost

4．On address mapping of cache, any block of main memory can be mapped to any line of cache, it is （P107~117 ）

总结映射：Direct Mapping——fixed main memory be mapped to fixed line of cache Associative Mapping——any block of main memory can be mapped to any line of cache,

Set Associative Mapping——the data in any block of main memory can be mapped to fixed set any l(way) of cache

A) Associative Mapping B) Direct Mapping C) Set Associative Mapping D) Random Mapping

P118 总结写策略：write through——as well as to cache

Write back——when the difference between cache and main memory is found

5. Cache’s write-through polity means write operation to main memory _______. A) as well as to cache B) only when the cache is replaced

C) when the difference between cache and main memory is found D) only when direct mapping is used

6. Cache’s write-back polity means write operation to main memory ______________.

a) as well as to cache

b) only when the relative cache is replaced

c) when the difference between cache and main memory is found d) only when using direct mapping

7. On address mapping of cache, the data in any block of main memory can be mapped to fixed line of cache, it is _________________.

A) associative mapping B) direct mapping C) set associative mapping D) random mapping

8.On address mapping of cache, the data in any block of main memory can be mapped to fixed set any line(way) of cache, it is _________________.

B) associative mapping B) direct mapping D) set associative mapping D) random mapping

二：计算题(from page 126)

Problem 4.1 , Problem 4.3 , Problem 4.4 , Problem 4.5 , , Problem 4.7, Problem 4.10

第五章作业

1.which type of memory is volatile?(P140 Table 5.1 熟记此表) A.ROM B. E2PROM C. RAM D. flash memory

2.which type of memory has 6-transistor structure?（P141 Figure 5.2(b)）

DRAM——is made with cells that store data as charge on capacitors (read refresh circuits but slower)

SRAM——binary values are stored using traditional flip-flop logic-gate configurations(faster & does not need refresh circuits)

A. DRAM B. SRAM C. ROM D. EPROM

3.Using hamming code, its purpose is of one-bit error. (P150第二段)

A. detecting and correcting B. detecting C. correcting D. none of all 4.Flash memory is （同1） .

A. read-only memory B. read-mostly memory C. read-write memory D. volatile 5.Which answer about internal memory is not true? （P139）

A. RAM can be accessed at any time, but data would be lost when power down.. B. When accessing RAM, access time is non-relation with storage location. C. In internal memory, data can’t be modified. D. Each addressable location has a unique address. Page161 Problems: 5.4 5.5 5.6 5.7 5.8

第六章作业 一、选择题 P180~183

RAID0——四个数据盘：不能纠错

RAID1——四个数据盘和四个copy盘：have copy ,mirror disk that contains the same data RAID2——四个数据盘和三个校验盘：make use lf a parallel access technique(have copy)

RAID3——四个数据盘和一个校验盘：(同2)+only a single redundant （只要知道有错误，无需其位置） RAID4——四个数据盘和一个校验盘：make use of independent access technique RAID5——distributes the parity strips across all disks

RAID6——two different parity calculations are carried out and stored in separate blocks on different disks

1. RAID levels_________make use of an independent access technique. A. 2 B. 3 C. 4 D. all

2. In RAID 4, to calculate the new parity, involves _ reads_P183.(two reads & two writes ) A. one B. two C. three D.four

3. During a read/write operation, the head is ------P164最后一段 A. moving B. stationary C. rotating D. above all

4. On a movable head system, the time it takes to position the head at the track is know as______.总结：（P171）

seek time——the time it takes to position the head at the track

Rotational delay——the time it takes for the beginning of the sector to reach the head