内容发布更新时间 : 2024/5/18 22:41:06星期一 下面是文章的全部内容请认真阅读。

2.

data segment

grade db 61,73,82,90,100,45 dup(70) avg1 db ? ;平均值的商 avg2 db ? max db ?

;平均值的余数 ;最大值

min db ?;最小值 data ends code segment

assume cs:code,ds:data

mov ax,data mov ds,ax mov si,0 mov bx,0 mov cx,50 mov ax,0 cbw add bx,ax inc si start:

l1: mov al,grade[si]

loop l1 mov ax,bx mov bl,50 div bl mov avg1,al mov avg2,ah mov si,0 ;找最大值 mov cx,50 mov al,grade[0] ja next0 mov al,grade[si] loop again0 mov max,al

again0: cmp al,grade[si]

next0: inc si

mov si,0 ;找最小值

mov bl,avg2 ;平均值的余数 call sub

mov dl,23h ;\分开不同数据 mov ah,2 int 21h

mov bl,avg1 ;平均值的商 call sub mov cx,50 mov al,grade[0] jna next1 mov al,grade[si] loop again1 mov min,al

again1: cmp al,grade[si]

next1: inc si

sub proc

mov ch,2 mov cl,4 mov al,bl and al,0fh cmp al,0ah jl next2

add al,37h ;\jmp down1

mov bl,min ;最小值 call sub

mov ax,4c00h int 21h

mov dl,23h ;\分开不同数据 mov ah,2 int 21h

mov dl,23h ;\分开不同数据 mov ah,2 int 21h

mov bl,max ;最大值 call sub

again2: rol bl,cl

next2: add al,30h ;\down1: mov dl,al

mov ah,2 int 21h dec ch jnz again2

ret

sub endp code ends

end start

3.

data segment

buf db 50 ;定义缓冲区 db 40 db 40 dup(0)

crlf db 0dh,0ah,'$' ;回车换行 data ends

stack segment stack db 100 dup(0) stack ends

code segment

assume ds:data, ss:stack, cs:code start: mov ax,data

mov ds,ax lea dx,buf

;输入字符串