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sql存储过程的加密和解密

★加密存储过程：

IF EXISTS (SELECT name FROM sysobjects WHERE name = 'encrypt_this' AND type = 'P') DROP PROCEDURE encrypt_this GO USE pubs GO

CREATE PROCEDURE encrypt_this

WITH ENCRYPTION ---只需要在创建时加入WITH ENCRYPTION即可 AS

SELECT * FROM authors GO

--查看存储过程文本：

EXEC sp_helptext encrypt_this 下面是结果集：

The object's comments have been encrypted. ----对象已经被加密

★解密存储过程：

CREATE PROCEDURE sp_decrypt(@objectName varchar(50)) AS begin

set nocount on

--CSDN：j9988 copyright:2004.04.15 --V3.1

--破解字节不受限制，适用于SQLSERVER2000存储过程，函数，视图，触发器 --修正上一版视图触发器不能正确解密错误 --发现有错，请E_MAIL：CSDNj9988@tom.com begin tran

declare @objectname1 varchar(100),@orgvarbin varbinary(8000)

declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)

DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)

declare @i int,@status int,@type varchar(10),@parentid int

declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int) insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)

select @number=max(number) from #temp set @k=0

while @k<=@number begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k) begin

if @type='P'

set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS '

else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS '

end)

if @type='TR' begin

declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)

select @parent_obj=parent_obj from sysobjects where id=object_id(@objectName) select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj if @tr_parent_xtype='V' begin

set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 ' end else begin

set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 ' end end

if @type='FN' or @type='TF' or @type='IF' set @sql1=(case @type when 'TF' then

'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end ' when 'FN' then

'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns char(1) with encryption as begin return @a end' when 'IF' then 'ALTER FUNCTION '+ @objectName+'(@a char(1)) returns table with encryption as return select @a as a' end)

if @type='V'

set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'

set @q=len(@sql1)

set @sql1=@sql1+REPLICATE('-',4000-@q) select @sql2=REPLICATE('-',8000) set @sql3='exec(@sql1'

select @colid=max(colid) from #temp where number=@k set @n=1

while @n<=CEILING(1.0*(@colid-1)/2) and len(@sQL3)<=3996 begin

set @sql3=@sql3+'+@' set @n=@n+1 end

set @sql3=@sql3+')'

exec sp_executesql @sql3,N'@Sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2 end

set @k=@k+1 end

set @k=0

while @k<=@number begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k) begin

select @colid=max(colid) from #temp where number=@k set @n=1

while @n<=@colid