仪器分析课后习题答案解析1 下载本文

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范文范例 精心整理 (3)

R??n4?rx,A?1??k?????r??k?1??x,A??2762?1.053?1??52.67?????4?1.053??52.67?1? ?0.65

(4)

?R1???R2??由

2?L1L2可知:

2LX?R??1.09??LS??X??183????514mR0.65???S?

211.解:

12.解:r2,1=1.05, Heff=0.99,

neff2?r2,1?22?1.05???16R???15876?r-1??16?1.5??1.05-1??2,1?2

L?neffHeff?15876?0.99?15.7m

?R1???R2??由

2?L1L2得:

?1????1.5?2?1L2

L2=2.25m

13解:t0=1.0min,tR=5.0min,Vs=2.0ml,q0=50ml/min

k?(1)容量因子

t'R5.0-1.0??4.0t01.0

(2)死体积:V0=t0*q0=1.0*50=50mL

(3)保留体积:VR=tR*q0=5*50=250mL (4)分配系数:K=kV0/VS=4*50/2=100 15解:

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范文范例 精心整理

mifA?iimsfsAs?m水??w水?

fiAi150?0.55?ms??0.0115?0.0094gfsAs174?0.58m水m环氧丙烷?100%?0.0617?100%?0.41%2.2679

word完美格式