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范文范例 精心整理 (3)
R??n4?rx,A?1??k?????r??k?1??x,A??2762?1.053?1??52.67?????4?1.053??52.67?1? ?0.65
(4)
?R1???R2??由
2?L1L2可知:
2LX?R??1.09??LS??X??183????514mR0.65???S?
211.解:
12.解:r2,1=1.05, Heff=0.99,
neff2?r2,1?22?1.05???16R???15876?r-1??16?1.5??1.05-1??2,1?2
L?neffHeff?15876?0.99?15.7m
?R1???R2??由
2?L1L2得:
?1????1.5?2?1L2
L2=2.25m
13解:t0=1.0min,tR=5.0min,Vs=2.0ml,q0=50ml/min
k?(1)容量因子
t'R5.0-1.0??4.0t01.0
(2)死体积:V0=t0*q0=1.0*50=50mL
(3)保留体积:VR=tR*q0=5*50=250mL (4)分配系数:K=kV0/VS=4*50/2=100 15解:
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范文范例 精心整理
mifA?iimsfsAs?m水??w水?
fiAi150?0.55?ms??0.0115?0.0094gfsAs174?0.58m水m环氧丙烷?100%?0.0617?100%?0.41%2.2679
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