年产600吨土霉素碱生产车间扩初设计毕业论文 下载本文

内容发布更新时间 : 2024/12/23 7:47:32星期一 下面是文章的全部内容请认真阅读。

Δtm= (14-9)/ln14/9=11.32 ℃

查《发酵设备》,取K=450×4.2=1890 kJ/ m3h℃

传热面积:F= Q总/(KΔtm)=4.79×105/1890×11.32=22.39㎡ 冷却水用量:W水 = Q总/KΔt

=4.79×105/4.2×(23-18) =2.28×104 ㎏/h

V水=2.28×10/1000×3600=0.0063 m/s

取5根蛇管:

V′= V水/5=0.0063/5=0.00126 m3/s

F′=F/5=22.39/5=4.478㎡

D内=(4 V′/Wsπ)1/2 =(4×0.000126/0.8π)1/2 =0.045m

查《化工工艺设计手册》,选φ50×2㎜

Re= d uρ/μ=0.045×0.8×1000/1105.59×10-5=3.26×104>104 属于湍流

L = F′/(πD内)=4.478/0.045π=31.68m

设每根长6.5 m, 则43.05/6.5=6.62 取7根 所以每根长6.5 m,每组7根。 7.1.2 中罐

7.1.2.1 几何尺寸

V中放=2.9 m3 设H0/D=3 V1=2.3m3

V1=π/4 D2H0=2.3

∴ D=0.99=1 H0=3D=3.0m 又∵Ha=1/4D=0.25m H b=0.025m

∴封头容积 V2 =π/4 D2(H b +1/6D)

=π/4×12×(0.025+1/6×1)

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=0.147 m3

校核 V= V1+ 2V2 = 2.3+2×0.147=2.6m3

∴假设合理。

罐体总高:H= H0+2(Ha+ H b )=3+2×(0.25+0.025)=3.54 m 液柱高:HL = H0η+ Ha+ H b=3×0.6+0.25+0.025=2.075m 7.1.2.2 搅拌器功率

7.1.2.2.1 不通气状况下搅拌功率

搅拌器直径:D i =1/3D =1/3=0.34 m 挡板宽度:B=0.1D=0.1 m 搅拌叶间距:S=2 D i =0.68 m 搅拌叶与罐底距离:C= D i = 0.34m

C +2S =0.34+1.36=1.7 m < HL= 2.07 m

C +3S =0.34+3×0.68=2.34 m > HL= 2.07 m ∴取3层搅拌器 令流体为牛顿型流体,符合全挡板条件:

ρ=1050 ㎏/ m3 n=170 r/min μ=0.1 N S/㎡ 则:Rem = Di2ρn/μ=0.342×240×1050/(60×0.1)

=4.85×103>4000 属过渡流

采用六箭叶涡轮搅拌器,查《发酵设备》,Np=3.7 轴功率:P0= N p Di5ρn3=43.5×0.5×(240/60)3×1050

=13.28kW

∵HL /D≠2.5

f校正=1/3[(D/ D i)(/Di)]1/2=1.44 ∴实际轴功率P*= f校正×P0=1.44×13.28=19.12kW 三层搅拌功率P= P* [1+0.6×(3-1)]=42.09kW 7.1.2.2.2 通气下的搅拌功率

P工况=P罐+1/2ρg HL

=1.01×105+0.03×106+1/2×1050×9.81×2.075=1.42×105 Pa Q标=VVm×V放=1.5×2.9=3.19 m3/min Qg= Q标P标T工况 /(P工况T标)

=4.35×1.01×105×(273+32)/(1.47×105×273)

=2.45 m3/min 通气准数:

Na = Qg/(D in) =2.45/240×0.343 =0.260>0.035

通气轴功率:

Pg =P(0.62-1.85 Na)

=42.09×(0.62-1.85×0.260) =5.85kW

N实际 =1.02 Pg/η1η2η

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=1.02×5.9/0.95×0.98×0.99 =6.53kW

η1 =0.95(皮带) η2 =0.98(轴皮带) η3 =0.99(轴)

查《化工工艺设计手册》,选用Y132M-4型电机 功率:11 kW,转数:1440 r/min,效率:87%

检验:7.5×87%=6.525 kW>6.5 kW

∴选型合适

7.1.1.2.3 通气管道

通气管径入口罐压: Pg = P罐+1/2ρg HL

=1.01×105+0.03×106+1/2×1050×9.81×2.075

=1.42×105 Pa

Qg = Q标P标T工况 /(P工况T标)

=4.35×1.01×105×(273+32)/1.42×105×273

=3.46 m3/min

通气管取2根, Ws=10m/s

d=(Q g/2×60×Ws×π/4)1/2

=[3.46/(2×60×10×π/4)]1/2 =0.061m

查《化工原理》,选φ65×2.5㎜

7.1.3 小罐 7.1.3.1 几何尺寸

V小罐=0.258 m3 设H0/D=3 V1=0.18 m3 V1=π/4 D2H0=0.18

∴ D=0.5m H0=2D=1m

又∵Ha=1/4D=0.125m H b=0.025m

封头容积V2=π/4 D2(H b +1/6D)

=π/4×0.502×(0.025+1/6×0.50) =0.020 m3

校核V= V1+ 2V2 = 0.50+2×0.020=0.540 m3

∴假设合理。

罐体总高:H= H0+2(Ha+ H b )=10+2×(0.125+0.025)=1.3 m

液柱高:HL = H0η+ Ha+ H b=1.0×0.6+0.125+0.025=0.75 m

7.1.3.2 通气管道(取1根)

P工况=P罐-P标

=1.01×105+0.5×105-1.01×105=0.5×105Pa Q标=VVm×V放=1.5×0.258=0.387 m3/min Qg = Q标P标T工况 /(P工况T标)

=0.387×1.01×105×(273+32)/0.5×105×273

=0.87 m3/min

取Ws=5m/s

空气管道d=[Qg/(60×Ws×π/4)]1/2

=[0.87/(60×10×π/4)]1/2 =0.043m

查《化工原理》,选φ50×2.5㎜

7.1.4 大罐配料罐 7.1.4.1 几何尺寸

η0=0.75 ρ=1050㎏/ m3 n=140r/min μ=0.1 N S/㎡ V配料=19.34 m3

V罐= V配料/η0=19.34/0.75=25.79 m3

取2个配料罐,V′罐=12.89m3, 取13 m3

取V1=10.8m3 令H0/D=2

V1=π/4 D2H0=10.8 m3

∴ D=1.9m H0=2D=3.8m 又∵Ha=1/4D=0.475m H b=0.04m 封头容积V2=π/4 D2(H b +1/6D)

=π/4×1.92×(0.04+1/6×1.9) =1.01 m

校核V= V1+ 2V2 = 10.8+2×1.01=12.82 m3

∴假设合理。

罐体总高:H= H0+2(Ha+ H b )=3.8+2×(0.475+0.04)=4.83 m 液柱高:HL = H0η+ Ha+ H b=3.8×0.6+0.475+0.04=2.8 m 7.1.4.2 搅拌器功率

搅拌器直径:D i =1/3D =0.63 m

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