内容发布更新时间 : 2024/11/16 16:26:11星期一 下面是文章的全部内容请认真阅读。
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??LH?p??
?5?7?5p??p?2???p???m?c?b?mg?c?b?cos????22?7m?c?b??10?7m?c?b?? 5p?2??mg?c?b?cos?214m?c?b?2?4?根据正则方程
???p?H?mg?c?b?sin?④ ?????对式两边求时间导得：
5p??H⑤ ?2?p?7m?c?b???????5p7m?c?b?2?5mg?c?b?sin?7m?c?b?2?5gsin?
7?c?b?故小球球心切向加速度
???5gsin? a??c?b??7
5.25解根据第二章§2.3的公式有：
??i????yipiz?zipiy???i?ziyJx??mi?yizi?1i?1?nn??i?xiz?i????zipix?xipiz??① Jy??mi?zixi?1i?1?nn??i?yix?i????xipiy?yipix??Jz??mi?xiyi?1i?1?nn根据泊松括号的定义：
????,??????s????????p??q?i?1??q??p???② ???所以
?J同理可知：
x,Jy???i?1?n?Jx?Jx?Jx?Jx??q??p??p??q??
?J由②得：
y,Jy?0, ?Jz,jz??0
??Jnx,Jy???Jx?Jy?Jx?Jy?????q?p??p?qi?1?????s? ??????Jx?Jy?Jx?Jy???Jx?Jy?Jx?Jy???Jx?Jy?Jx?Jy??????????x?p??p?x?????y?p??p?y?????z?p??p?z???i?1?ixixi?iyiyi?izizi???i?i??i? ???xipiy?yipix??Jzi?1n同理可得：
?Jy,Jz?Jx, ?Jz,Jx??Jy
?5.26解 由题5.25可知Jx,Jy,Jz的表达式 因为
?py?py?py?p??p??1,?0;?0,?0,?0 ?p??p??x?y?z故
???Jx?py?Jx?pyJx,py?????q?p??p?qi?1??????s? ???n??yp?zp??Jxiiziiy????y?yii?1
??piz?pzi?1n同理可求得：
?n??xp?yp?n?JziiyiixJz,py??????pix??px
?y?yii?1i?1??J,p????Jyyyy?0