ݷʱ : 2024/12/23 11:05:57һ µȫĶ
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CH3A:BrB:BrCH3CH2BrC:CH3
CH3CH2BrBrD:CH3CH2
CH3BrBr+CH3+BrHBrCH3BrCH2CH3Br+CH3KOC(CH3)3CH2CH2CH2O3OZn,H2O2HCHO+OCC
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ھ ±
1л
CH2Cl2CH2CH2CH2ClClCH2=CCHCH=CHCH2BrCH3
14ȶ 23ȣ6壭14ϩ
CH2CH3CH3CHBrCHCHCH3
2ȣ3ϩ 23һ4
BrClClClCH3
4屽 3Ȼϩ
F2C=CF2CH3Br
ķϩ 41廷ϩ 2длĽṹʽ
1ϩ 2
CH2=CHCH2Cl
345ȣ2Ȳ 4һ廷
CH2Br
CH3CCCHCH2Cl
Br
CH3CH2CH2BrCL2C=CH2CCl2F2HCCl3
3зӦʽ
(1)CH3CH=CH2+HBrCH3CHCH3NaCNCH3CHCH3BrCN
ROOR+CHCH=CHHBr(2)32H2O(KOH)CH3CH2CH2OHCH3CH2CH2Br
(3)CH3CH=CH2+Cl20500CClCH2CH=CH2Cl2+H2OClCHCHCHCl22OH
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Cl(4)
+Cl2Cl2KOH
(5)NBSBrKICH3COCH3I
CH3(6)CH3CHCHCH3CH3OH(7)(CH3)3CBr+KCN
PCl5CH3CHCHCH3NH3CH3ClCH2=C(CH3)2
CH3CHCHCH3NH2
C2H5OH(8)CH3CHCH3OHPBr5CH3CHCH3BrAgNO3/C2H5OHCH3CHCH3ONO2
(9)C2H5MgBr+CH3CH2CH2CH2CCHCH3CH3+CH3CH2CH2CH2CCMgBr
CH3COOHClCH=CHCH2OOCCH3+NaCl(10)ClCH=CHCH2Cl+CH3COONa
(11)CHCH+2Cl2Cl2CHCHCl2KOH(C2H5OH)(1mol)ClC=CClHCl
NaCNNH3+CH2CNCH2NH2CH2OC2H5CH2ICH2Cl(12)C2H5ONaNaI/CH3COCH3H2O,-OHCH2OH
4÷ʽʾCH3CH2CH2CH2BrлﷴӦҪ
1 CH3CH2CH2CH2OH 3 CH3CH2CH2CH2MgBrCH3CH2CH2CH3,HCCMg2 CH3CH2CH=CH2 4 CH3CH2CH2CH2I
6 CH3CH2CH2CH2CN
ҳ 96 ҳ
5 CH3CH2CH2CH2NH2
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7 CH3CH2CH2CH2ONO2
9 CH3CH2CH2CH2CH2CH2CH2CH3 5ûѧл: ⣺1 Br2,aq Һ 2 CH3CH=CHCl ɫ CH2=CHCH2Cl ɫ Ȼ ȴ ȱ CH3CH2CH2Cl 8 CH3CCCH2CH2CH2CH3
10 CH3CH2CH2CH2N(CH3)2
Һ ȻȻҲӦ 3 1 2嶡 1 Һ ɰɫȻɵɫ ɫ⻯ 4 ȱ 21 Һ Ӧ Ȼ ȲȻ 6и黯ﰴӦٶȴС˳У ⣺1SN1Ӧ
CH3
(a)(CH3)3CBr,>CH3CH2CHBr>CH3CH2CH2CH2Br,
(b)CHCH3BrCH2Br>>CH2CH2Br
2SN2Ӧ
(a)CH3CH2CH2Br>(CH3)2CHCH2Br>(CH3)3CCH2Br
(CH3)3CBr
CH3(b)CH3CH2CH2CH2Br>CH3CH2CHBr>7и黯ﰴȥ廯״УдĹʽ ⣺1
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