重庆一中2018-2019学年下期2020级第一次月考八年级数学试卷

内容发布更新时间 : 2024/5/17 17:51:43星期一 下面是文章的全部内容请认真阅读。

?70?x?10?70?x?22或 ????105?2y?55?105?2y?25?x?60?x?48或? ???y?25?y?40?32(舍)?x?60,y?25.

∴原总花费为:5x?140y?700?5?60?140?25?700?3100(元).

三、解答题(本大题2个小题,每小题8分,共16分)解答时每小题必须给出必要的演算过程或推理步骤. 19.因式分解:

解:(1)原式?2xy(y?x) (2)原式?(a?b)x?a

?2??(a?b)(x?3)(x?3)

20.解下列分式方程:

解:(1)去分母得:3x?3(x?2)?x?1 整理得:5x?5

?x?1

检验:当x?1时,x?2?0 帮原式分式方程的解为:x?1

解:(2)去分母得:x(x?1)?2?x?1 整理得:x?1

检验:当x?1时,分母x?1?0 故x?1为增根 从而原分式方程无解.

四、解答题:(本大题4个小题,每小题10分,共40分)解答时每小题必须给出必要的演算过程或推理步骤.

21.证明:在YABCD中,AD?BC,AB?CD,?A??C 又DE?BF?AD?DE?BC?BF

22?AE?CF

在△ABE和△CDF中,

?AE?CF?

??A??C ?AB?CD?

∴△ABE≌△CDF(SAS) ∴?APE??CDF.证毕.

??x?1?x??15?????1?x??整数解为:x?0,1,2 22.解:?1?52x??2x?1?4??2?23?x2?4x?4?x?1??3x?1? ???x?1???2x?1?x?1x?1(x?2)??(x?2)(x?2)x?1??x?2

x?1x?2由于分母x?1?0,x?2?0即x?1,2. 故当x?0时,原式?x?2?2. 23.解:(1)

单价 销售总额 数量 甲 设为x 6000 乙 1.5x 8100 6000 x8100 1.5x∴

60008100??5?x?120(元) x1.5x答:三月份甲款衬衣的单价是120元 (2)设该商家要卖出甲款衬衣y件, 数量 甲 乙 y 200?y 新单价 120?(1?20%) 1.5?120?50% 18720, ∴总销售额?120?(1?20%)y?1.5?120?50%?(200?y)…?96y?90(200?y)…18720

?y?120(件)

答:该商家至少要卖出甲款衬衣120件.

24.解:(1)在Rt△ACE中,|CE|?|AC|2?|AE|2?(210)2?22?6 在Rt△BCE中,|BE|?|BC|?|CE|?10?6?8

2222?|AB|?|BE|?|AE|?8?2?6

?SYABCD?|AB|?|CE|?6?6?36

(2)延长BA,CF交于点M

在△GBC中,D为CG的中点,FD∥BC?F为BG的中点?|FQ|?|AF|?又AF∥BC?△MAF∽△MBC 从而F为MC的中点

在Rt△CEM中,|EF|?|FC|?|FM|.证毕!

五、解答题:(本大题2个小题,25题10分,26题12分,共22分)解答时每小题必须给出必要的演算过程或推理步骤. 25.解:(1)?1|BC| 23 5(2)x(x?4)?(2x?4)?12

?x2?2x?8?0 ?(x?4)(x?2)?0

?x?4?0或x?2?0 ?x??4或x?2

(3)m?x?(?3x)?1?x?3x

22n?8x?(?6)?1?8x?6

则m?n?x?5x?6?0

2?(x?6)(x?1)?0且x?1?x?6

?x?6?0????1?x?6 ?x?1?026.解:(1)OC:y?33x?tan?cos???cos?30? 33BC:y??33x?33?tan?CBO???CBO?30? 33?|AO|?33?|OB|?9?339|CH|??|OH|??|BH|, ?22过C作CH?OB于H??∴S△OBC?113327?|OB|?|CH|??9??3 2224(2)作直线l1关于x轴的对称直线l3,过E作EF?l3,则?EBF?30??|EF|?1|BE|. 2过C作CF0?l3于F0,由(1)知|CO|?|BC|?2|CH|?33,故BF0?339,|CF0|?3|BF0|? 2219|CE|?|BE|?|CE|?|EF|…CF0?,此时E点即为CF0与x轴的交点,

22??339????3?x?? ?933???CF0:y?22?由(1)知A(0,33),B(9,0)?AB的中点C?,????22??令y?0可得x?6,当E为(6,0)时,|CE|?易知CF0的倾斜解为120?19|BE|取最小值 22(3)由于?COE?30?,?OEC?60???OCE?90?

又|OC|?33,从而|CE|?3?|DE|,|OE|?2|OE|?6?|OD|?|OE|?|DE|?6?3?3

?933??O(3,0),E(6,0),C?,?

?22?易得:C?3?3cos60??,3sin?60????

?????E?(3?3cos(??),3sin(??))?E?(3?3cos?,?3sin?)

31cos??sin?sin???60??sin?60?????sin?3cos??sin?22???? cos?60?????cos?sin???30??313sin??cos?sin??cos?22kC?E?

?C?E?:y?3sin??3cos??sin?(x?3?3cos?)

3sin??cos?令y?0?xN?3sin?(3sin??cos?)?3(1?cos?)

3cos??sin?3sin2??sin?cos??3cos??sin??3cos2??sin?cos? ?3?3cos??sin??3?3?3cos??sin?33??3

3cos??sin?3cos??sin??33?3

2sin???60??331211 ?3?0?????2sin???60??sin???60??3sin240?sin300?令

?60????60??180?或240????60??300?或360????60??420?(画出y??0????120?或180????240?或300????360?

?3?cos??sin???CE:y?3sin??(x?3?3cos?)??3sin??cos? ?3?l:y?x2?3?1的图像可知) sinx?33cos??sin?x?3sin??(x?3?3cos?) 33sin??cos??3cos??sin?3?3cos??sin????x?3sin???3(1?cos?) ?33sin??cos??2sin??cos??3sin???xM?3cos??sin??3(1?cos?)3sin??cos? 3cos??sin?1?3sin??cos?3?33sin?(3sin??cos?)?33(1?cos?)(3cos??sin?)

3(3cos??sin?)?(3sin??cos?)9sin2??33sin?cos??9cos??33sin??9cos2??33sin?cos??

4cos?

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