液压传动-东南大学-习题解答1-7?- 百度文库

ݷʱ : 2024/12/27 16:20:18һ µȫĶ

A1?1?10?2m2иǻA2?0.8?10?2m2ѹP1 =0.9MPa,q1=12L/minʧй©:

1)׳ͬʱ(F1?F2)غٶȸΪ? 2)Iܸʱ(F1?0)2ܳܶٸ? 3)2ܸʱ(F2?0)1ܳܶٸ? ⣺

1F1?p1A1?p2A2?

F2?p2A1

0.9?106?1?10?2?p2?0.8?10?2?p2?1?10?2 F2?p2A1?0.5?1?104

q12?10?3v1???0.02m/s ?2A160?1?10q212?10?3?0.8v2???0.016m/s

A160?1?10?22F1?p1A1?p2A2?0 p2=1.125

F2?p2A1?1.125?1?11250N 3F2?0

F1?p1A1?p2A2?0.9?1?9000N

v?qq? 2A?d4 ٶͬ

5 -5 Һѹͼ5-27ʾѹΪP1 ,ֱΪD,ֱΪd,ѹP2Ϊ? ⣺

p1?D24?p2?d24

D2p2?p12

d 17 ҳ

5-6 һ˻׿ʱòӣʱҺ˸׵иǻ׿˵ٶȾΪ0.1 m/sʱѹΪ25000N֪q=25L/minѹp2=0. 2MPa: I)׺ͻֱD,d

2) ׼ں񣬸ͲΪ45֡

3)˽½ӣͲ̶װΪ1.5mУ˻˵ȶԡ ⣺

qq25?10?3?41ӣ v?? ?0.1?22A?d60?3.14?d4 d=73mm

qq4?25?10?3˽иǻv?? ?0.1?A?(D2?d2)60??(D2?752)44?25?10?3D?75??10?0.0053

60??22 D=105 103 mm

3.14?0.1052?25000N??P??p ʱF?pA?p444?D2?D2P12.89+0.2MPa 2Ͳıں D/??10

1.5?3?106?0.0105????1.9mm 62[?]2?600/5?10֤ʵ 3Уˣ

PyD 18 ҳ

?1?85 ?2?2 ?1?2?120

l/rK?1.5?4/d?6/0.07?82

3.14D4DrK?J/A???

64A4FFF??K?K

nK3?490??0.0752fA2.163656254FK????2.2?106N?11?1.43328618576143E-51?l1?5000?2()211.5rk()0.03842FF2200000 F??K?K??733333NnK335-7 Һѹͼ5-28ʾ׾D =63mm˾d=28mmýڿɵʽװãλǻСdc = 35 min󻺳г1c =25mm˶m = 2000K˶ٶv0=0, 3m/s,ĦFf=950NǻѹPp=7MPaʱ󻺳ѹͲǿȲʱô? ⣺

E1?pcAclc

E2?ppAplc?Ac?Ap?12mv?Fllc 22?4(D2?dc)?2.13?10?3m2 (D2?dc)?2.5?10?3m2

2?4pc?E2?AclcppAplc?12mv?Fflc2 Aclc7?106?pc??4(D2?d2)?0.025?0.5?2000?0.32?950?0.025??(D2?d2c)4

?0.025 19 ҳ

pc?437.5?90?23.75?9.35MPa

5.3851E-5pmaxmv2?pc???2Aclc2000?0.322??4??3.74?0.035?0.0252

𰸣pmax?11.02MPa

E1?pcAclc?0.025?0.083 0.3ʱ䣺t?l0.025??0.083s v0.3ʵڣг̡

20 ҳ

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