ݷʱ : 2024/12/27 16:20:18һ µȫĶ
A1?1?10?2m2иǻA2?0.8?10?2m2ѹP1 =0.9MPa,q1=12L/minʧй©:
1)׳ͬʱ(F1?F2)غٶȸΪ? 2)Iܸʱ(F1?0)2ܳܶٸ? 3)2ܸʱ(F2?0)1ܳܶٸ? ⣺
1F1?p1A1?p2A2?
F2?p2A1
0.9?106?1?10?2?p2?0.8?10?2?p2?1?10?2 F2?p2A1?0.5?1?104
q12?10?3v1???0.02m/s ?2A160?1?10q212?10?3?0.8v2???0.016m/s
A160?1?10?22F1?p1A1?p2A2?0 p2=1.125
F2?p2A1?1.125?1?11250N 3F2?0
F1?p1A1?p2A2?0.9?1?9000N
v?qq? 2A?d4 ٶͬ
5 -5 Һѹͼ5-27ʾѹΪP1 ,ֱΪD,ֱΪd,ѹP2Ϊ? ⣺
p1?D24?p2?d24
D2p2?p12
d 17 ҳ
5-6 һ˻ʱòӣʱҺ˸иǻ˵ٶȾΪ0.1 m/sʱѹΪ25000N֪q=25L/minѹp2=0. 2MPa: I)ͻֱD,d
2) ںͲΪ45֡
3)˽½ӣͲ̶װΪ1.5mУ˻˵ȶԡ ⣺
qq25?10?3?41ӣ v?? ?0.1?22A?d60?3.14?d4 d=73mm
qq4?25?10?3˽иǻv?? ?0.1?A?(D2?d2)60??(D2?752)44?25?10?3D?75??10?0.0053
60??22 D=105 103 mm
3.14?0.1052?25000N??P??p ʱF?pA?p444?D2?D2P12.89+0.2MPa 2Ͳıں D/??10
1.5?3?106?0.0105????1.9mm 62[?]2?600/5?10֤ʵ 3Уˣ
PyD 18 ҳ
?1?85 ?2?2 ?1?2?120
l/rK?1.5?4/d?6/0.07?82
3.14D4DrK?J/A???
64A4FFF??K?K
nK3?490??0.0752fA2.163656254FK????2.2?106N?11?1.43328618576143E-51?l1?5000?2()211.5rk()0.03842FF2200000 F??K?K??733333NnK335-7 Һѹͼ5-28ʾD =63mm˾d=28mmýڿɵʽװãλǻСdc = 35 minг1c =25mm˶m = 2000K˶ٶv0=0, 3m/s,ĦFf=950NǻѹPp=7MPaʱѹͲǿȲʱô? ⣺
E1?pcAclc
E2?ppAplc?Ac?Ap?12mv?Fllc 22?4(D2?dc)?2.13?10?3m2 (D2?dc)?2.5?10?3m2
2?4pc?E2?AclcppAplc?12mv?Fflc2 Aclc7?106?pc??4(D2?d2)?0.025?0.5?2000?0.32?950?0.025??(D2?d2c)4
?0.025 19 ҳ
pc?437.5?90?23.75?9.35MPa
5.3851E-5pmaxmv2?pc???2Aclc2000?0.322??4??3.74?0.035?0.0252
𰸣pmax?11.02MPa
E1?pcAclc?0.025?0.083 0.3ʱ䣺t?l0.025??0.083s v0.3ʵڣг̡
20 ҳ