内容发布更新时间 : 2024/12/23 18:57:23星期一 下面是文章的全部内容请认真阅读。
EIv????积分得:
Mex?Me 3aMex2EIv????Mex?C1 (3)
3a2Mex3x2EIv???Me?C2x?D2 (4)
3a62x?3a时,vB?0;代入(4)式,得 3Mea39a2??Me?C23a?D2?0
22x?3a时,vC1?vC2;?C1??C2
联立解得系数C1,C2,D2
x?0时,?A?Mea 6EIMea x?3a时,?B??3EI7.解:?C1??B1Fa2??2EI,vC1Fa3, ??3EIFa3Fa25Fa3得vB?? ??a??13EI2EI6EI?B24Fa22Fa28Fa3,vB?? ????23EI2EIEIFa22Fa25Fa2?????
2EIEI2EI
叠加原理得:
?B??B1??B2vB?vB1?vB28. 解:?A18Fa35Fa37Fa3?????
3EI6EI2EIql3ql4ql3?,vA??,?C??A?126EI8EI8EI49
ql4,vC??24EI,
vA2ql4ql3l5ql4, ??????24EI8EI248EIql3ql37ql3???6EI8EI24EI叠加原理得:
?A??A1??A2vA?vA?vA
ql45ql411ql4?????
128EI48EI
9. 解:v?Fl3Fl2C1?48EI?Fl2,B1?16EI vC2?Fl316EI,?B2??3EI ????13Fl2B?B1??B248EI vFl2C?vC1?vC2? 24EI 10.
解
:
?7Fa2C1?6EI3??q(2a)qa3C2?A??24EI??3EI
v??qa3qa4C2A?a?3EI?a?3EI叠加原理得:
???5qa3C?C1??C26EI 2qa4vC?vC1?vC2??3EI
ql2?l11. 解:?A??Melql313EI??6EI,vC21??2l2ql46lEI(l2?4)??32EI
50
48EI叠加原理得:
vqa4C1??EI
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