城市物流配送方案优化模型 数学建模 - 图文

内容发布更新时间 : 2024/11/6 9:40:51星期一 下面是文章的全部内容请认真阅读。

plot(m,n,'.r') %?-?·í? for i=1:272 Y1=Road(i,3); X1=Road(i,2); Y2=Road(i,5); X2=Road(i,4);

line([X1,X2],[Y1,Y2]); hold on end

for x=1:19

str= num2str(Road(x,1)); plot(X1(x),Y1(x),'ro')

10.2.4 画卸货点与用户图 m=jpoint(:,1); n=jpoint(:,2); plot(m,n,'.r');

10.2.5 画三维图

x=[2,3,4,0,2,3,0,1,4]; y=[2,2,2,3,3,3,4,4,4];

z=[80,82,84,79,61,65,84,84,86];

subplot(2,1,1);stem3(x,y,z);title('RAW DATA'); xi=0:0.1:4;yi=2:0.2:4; [XI,YI]=meshgrid(xi,yi);

ZI=griddata(x,y,z,XI,YI,'v4');

subplot(2,1,2);mesh(XI,YI,ZI);title('GRIDDATA');

10.2.6 floyd算法matlab代码 function [d,r]=floyd(a) n=size(a,1); d=a;

for i=1:n for j=1:n r(i,j)=j; end

end for k=1:n for i=1:n for j=1:n

if d(i,k)+d(k,j)

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end end end end

10.2.7 最优哈密尔顿圈matlab代码 clc,clear

a(1,2)=56;a(1,3)=35;a(1,4)=21;a(1,5)=51;a(1,6)=60; a(2,3)=21;a(2,4)=57;a(2,5)=78;a(2,6)=70; a(3,4)=36;a(3,5)=68;a(3,6)=68; a(4,5)=51;a(4,6)=61; a(5,6)=13; a(6,:)=0; a=a+a';

c1=[5 1:4 6]; L=length(c1); flag=1;

while flag>0 flag=0; for m=1:L-3 for n=m+2:L-1

if a(c1(m),c1(n))+a(c1(m+1),c1(n+1))

c1(m+1:n)=c1(n:-1:m+1); end end end End sum1=0; for i=1:L-1

sum1=sum1+a(c1(i),c1(i+1)); end

circle=c1; sum=sum1;

c1=[5 6 1:4];%改变初始圈，该算法的最后一个顶点不动 flag=1;

while flag>0 flag=0; for m=1:L-3 for n=m+2:L-1

if a(c1(m),c1(n))+a(c1(m+1),c1(n+1))< a(c1(m),c1(m+1))+a(c1(n),c1(n+1)) flag=1;

c1(m+1:n)=c1(n:-1:m+1); end

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end end end sum1=0; for i=1:L-1

sum1=sum1+a(c1(i),c1(i+1)); end

if sum1

circle,sum 运行结果：

circle = 1 2 4 6 7 5 3 8 sum = 84.4332

10.2.8 0-1规划lingo代码 MODEL: SETS:

Logistics/L1..L9/:x; Customer/C1..C100/:w;

Link(Logistics,Customer):z,d; ENDSETS DATA:

w=@OLE('D:\\weight.XLS'); d=@

OLE('D:\\distance.XLS'); ENDDATA

Min=@sum(customer(j):w(j)*link(i,j):d(i,j)*z(i,j)); x(9)=1;

@for(customer(j):

@sum(link(i.j):z(i,j))=1); @for(logistics(i):

@sum(Logistics(i):x(i))=6) @for(Link(i,j):@bin(z)); @for(L(i):@bin(x)); END

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