渡槽设计部分计算书

内容发布更新时间 : 2024/12/27 2:25:26星期一 下面是文章的全部内容请认真阅读。

??1?1?2?s?0.016?0.85?b?0.468,

fcb?h011.9?1000?0.016?265As???168.2mm2??minbh0?397.5mm2fy30022(A?404mm)A??bh?397.5mms实min0取s,选取B12@280,

受力筋总面积为856mm/m,分布筋面积应大于

2

15%?856mm2/m?128.4mm2/m

侧墙底部迎水面限裂验算:

?te?有效配筋率:

AsA?s?0.7Ate2ab,

?skMk??126.7N/mm20.87h0As?maxd????max??0.25mm?30?c?0.07??0.21mm????Es??te?,

?sk?满足限裂要求。

3、底板计算

计算简图

按端部截面配筋,背水面a=35mm,c=25mm 迎水面a=40mm,c=30mm

h0?h?a?260mm,h?a'?265mm,M=24.36KN.m,N=53KN

e0?Mh?460mm??a?110mmN2

N作用于纵向钢筋范围之外,属于大偏拉构件,上侧

h300e?e0??a?460??40?350mm22迎水面受拉,下侧受压, As'?2KNe?fc?sbbh0fy'h0?a'??1.15?53?103?350?0.358?1000?2602??0300??260?35?'2A??bh?0.15%?1000?260?390mmmin0取s,选配B12@280

As'实?404mm2/m??minbh0,

?s?KNe?fy'As'h0?a'2fcbh0???1.15?53?10?350?300?390?225?0211.9?1000?2603所以应该按最小配筋率配筋

As??minbh0?0.15%?1000?260?390mm2,选取

B12@280

As实?404mm2

AsAs?te???0.505Ate2ab底板端部限裂验算:

Nk?es?2?sk?1?1.1?325.4N/mm??As?h0?

?sk?d??max???lmax??0.20mm?30?c?0.07??0.19mm????Es??te?满足抗裂要求。 跨中最大弯矩截面

取a=35mm, h0?h?a?265mm,hw?h0?265mm,

hw?0.265?4.0KV?1.15?47?54.05KNmaxb,

0.25fcbh0?0.25?11.9?1000?265?788.4KN?KVmax

故截面尺寸满足抗剪要求

KM1.15?12?106?s???0.0222fcbh011.9?1000?265,

??1?1?2?s?0.02?0.85?b?0.468fcb?h011.9?1000?0.02?265As???mm2??minbh0?397.5mm2fy300故按最小配筋率配筋,选取B12@280(

As实?404mm2)

斜截面受剪承载力计算:KVmax?54.05KN,

0.7ftbh0?0.7?1.27?1000?265?235.585?KVmax?54.05KN

故不需要由计算确定抗剪腹筋

3、横杆计算

横杆间距s=2.3m,

?ga?qa??S??0.08?1?25?2.5?1??2.3?10.35KN/m,

Nd?Rd?S?15.3?2.3?35.19KNgb?0.3?0.3?25?2.25KN/m,

梁端弯矩与ND组合配筋计算

a=40mm,a’=35mm,M=4.5KN.m,N=35.19KN

Mhe0??128mm??a?110mmN2,N作用在As与As’之外,为

大偏拉,

e'?h?a'?e0?150?35?110?225mm2,

e?e0?A?'sh?a?128?150?40?18mm2,

2KNe?fc?sbbh0fy'h0?a'??1.15?35.19?103?18?11.9?0.358?300?2602??0300?2252?bh?0.15%?300?260?117mm按最小配筋率配筋min0

选配2B10

?s?(As'实?157mm2??minbh0)

3KNe?fy'As'h0?a'2fcbh0???1.15?35.19?10?18?300?157??260?35??011.9?300?26022?bh?0.15%?300?260?117mm按最小配筋率配筋min0,

选配2B10

(As'实?157mm2??minbh0)

0.7ftbh0?0.7?1.27?300?260?69.342?KVmax?40.5KN满

足截面尺寸抗剪要求。

跨中最大弯矩与Nd组合配筋计算:a=35mm,a’=40mm

Mhe0??34.4mm??a?110mmN2M=1.21KN.m, ,N作用在As

与As’之间,为小偏拉

e'?e0?h?a'?34.4?150?40?144.4mm2,

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