1
化学反应动力?/p>
第二章习?/p>
1
?/p>
The first-order gas reaction SO
2
Cl
2
?/p>
SO
2
+ Cl
2
has k = 2.20
?/p>
10
-5
s
-1
at 593K,
(1)
What percent of a sample of SO
2
Cl
2
would be decomposed by heating at 593K for 1
hour?
(2)
How long will it take for half the SO
2
Cl
2
to decompose?
解:一级反应动力学方程为:
t
k
e
Cl
SO
Cl
SO
?/p>
?/p>
?/p>
?/p>
?/p>
]
[
]
[
2
2
2
2
?/p>
t
k
e
Cl
SO
Cl
SO
?/p>
?/p>
?/p>
?
]
[
]
[
2
2
2
2
(1)
反应?/p>
1
小时时:
60
60
10
20
.
2
2
2
2
2
5
]
[
]
[
?/p>
?/p>
?/p>
?/p>
?/p>
?/p>
e
Cl
SO
Cl
SO
?
=0.924=92.4%
已分解的百分数为?/p>
100%-92.4%=7.6%
(2)
?/p>
2
1
]
[
]
[
2
2
2
2
?/p>
?/p>
Cl
SO
Cl
SO
时,
7
.
31506
2
1
ln
1
?/p>
?/p>
?/p>
k
t
s
5
2
1
10
2
.
2
693
.
0
?/p>
?/p>
?
t
= 31500 s = 8.75 hour
2
?/p>
T-butyl
bromide
is
converted
into
t-butyl
alcohol
in
a
solvent
containing
90
percent
acetone and 10 percent water. The reaction is given by
(CH
3
)
3
CBr + H
2
O
?/p>
(CH
3
)
3
COH + HBr
The following table gives the data for the concentration of t-utyl bromide versus time:
T(min)
0
9
18
24
40
54
72
105
(CH
3
)CBr (mol/L)
0.1056
0.0961
0.0856
0.0767
0.0645
0.0536
0.0432
0.0270
(1)
What is the order of the reaction?
(2)
What is the rate constant of the reaction?
(3)
What is the half-life of the reaction?
解:
(1)
设反应级数为
n
,则
n
A
k
dt
A
d
]
[
]
[
?/p>
?
?/p>
kt
A
A
n
n
?/p>
?/p>
?/p>
?/p>
1
1
]
[
1
]
[
1
?
?/p>
n=1
,则
]
[
]
[
ln
1
A
A
t
k
?
?/p>
t = 9
01047
.
0
0961
.
0
1056
.
0
ln
9
1
?/p>
?/p>
k
?/p>
t = 18
01167
.
0
0856
.
0
1056
.
0
ln
18
1
?/p>
?/p>
k
t = 24
01332
.
0
0767
.
0
1056
.
0
ln
24
1
?/p>
?
k
?/p>
t = 40
01232
.
0
0645
.
0
1056
.
0
ln
40
1
?/p>
?/p>
k
t = 54
01256
.
0
?/p>
k
?/p>
t = 72
01241
.
0
?/p>
k
?/p>
t = 105
01299
.
0
?/p>
k